thrust::copy

Defined in thrust/copy.h

template<typename InputIterator, typename OutputIterator>
OutputIterator thrust::copy(InputIterator first, InputIterator last, OutputIterator result)

copy copies elements from the range [first, last) to the range [result, result + (last - first)). That is, it performs the assignments *result = *first, *(result + 1) = *(first + 1), and so on. Generally, for every integer n from 0 to last - first, copy performs the assignment *(result + n) = *(first + n). Unlike std::copy, copy offers no guarantee on order of operation. As a result, calling copy with overlapping source and destination ranges has undefined behavior.

The return value is result + (last - first).

The following code snippet demonstrates how to use copy to copy from one range to another.

See also

https://en.cppreference.com/w/cpp/algorithm/copy

#include <thrust/copy.h>
#include <thrust/device_vector.h>
...

thrust::device_vector<int> vec0(100);
thrust::device_vector<int> vec1(100);
...

thrust::copy(vec0.begin(), vec0.end(),
             vec1.begin());

// vec1 is now a copy of vec0

Parameters

• first – The beginning of the sequence to copy.

• last – The end of the sequence to copy.

• result – The destination sequence.

Template Parameters

• InputIterator – must be a model of Input Iterator and InputIterator's value_type must be convertible to OutputIterator's value_type.

• OutputIterator – must be a model of Output Iterator.

Returns

The end of the destination sequence.

Pre

result may be equal to first, but result shall not be in the range [first, last) otherwise.