thrust::transform

Defined in thrust/transform.h

template<typename DerivedPolicy, typename InputIterator1, typename InputIterator2, typename OutputIterator, typename BinaryFunction> OutputIterator thrust::transform(const thrust::detail::execution_policy_base<DerivedPolicy> &exec, InputIterator1 first1, InputIterator1 last1, InputIterator2 first2, OutputIterator result, BinaryFunction op)

This version of transform applies a binary function to each pair of elements from two input sequences and stores the result in the corresponding position in an output sequence. Specifically, for each iterator i in the range [first1, last1) and j = first + (i - first1) in the range [first2, last2) the operation op(*i,*j) is performed and the result is assigned to *o, where o is the corresponding output iterator in the range [result, result + (last - first) ). The input and output sequences may coincide, resulting in an in-place transformation.

The algorithm’s execution is parallelized as determined by exec.

The following code snippet demonstrates how to use transform to compute the sum of two ranges using the thrust::host execution policy for parallelization:

#include <thrust/transform.h>
#include <thrust/functional.h>
#include <thrust/execution_policy.h>
...

int input1[6] = {-5,  0,  2,  3,  2,  4};
int input2[6] = { 3,  6, -2,  1,  2,  3};
int output[6];

thrust::plus<int> op;

thrust::transform(thrust::host, input1, input1 + 6, input2, output, op);

// output is now {-2,  6,  0,  4,  4,  7};