cuda::ipow

Defined in the <cuda/cmath> header.

namespace cuda {

template <typename T, typename E>
[[nodiscard]] __host__ __device__ constexpr
T ipow(T base, E exp) noexcept;

} // namespace cuda

The function computes the integer base raised to the power of exp.

Parameters

• base: The base value.

• exp: The exponent value.

Return value

• The result of raising base to the power of exp.

• If exp is 0 or base is 1, the result is 1.

• Otherwise, if exp is negative, the result is 0.

Constraints

• T is an integer type.

• E is an integer type.

Preconditions

• if base is 0, then exp must be non-negative.

Example

#include <cuda/cmath>
#include <cuda/std/cassert>

__global__ void ipow_kernel() {
    assert(cuda::ipow(0, 0) == 1);
    assert(cuda::ipow(2, 2) == 4);
    assert(cuda::ipow(99, 1) == 99);
    assert(cuda::ipow(4, 7) == 16384);
    assert(cuda::ipow(-1, 3) == -1);
    assert(cuda::ipow(1, -1) == 1);
    assert(cuda::ipow(23, -1) == 0);
}

int main() {
    ipow_kernel<<<1, 1>>>();
    cudaDeviceSynchronize();
}

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